Solve Algebraically 2^3-x=565

x  =  3  − log  565/  log  2  =  −  6.142107057

Step-by-step explanation:

2^3-x =565

Log 2^3-x =  log  565

(3-x) times log 2 = log 565

3 −  x  =  log  565 / log  2

3  −  log  565 / log  2  =  x

x  =  3  − log  565/  log  2  =  −  6.142107057

ans789

step-by-step explanation:

i think it will be zero as slope has a formula of difference between initial and final distance divided by itz time interval