Find three consecutive even integers such that their sum is 50 more than the largest integer

This is how I'd solve it:

1st no. = 2x                (2x)+(2x+2)+(2x+4)=(2x+4)+50
2nd no. = 2x+2                                  6x+6=2x+54
3rd no. = 2x+4                                       4x=48
                                                                x=12

Substitute the x value, and your numbers are 24, 26, and 28.  To check: their sum (78) is 50 more than the largest integer (28).