Complete the two-column proof using the answers in the bank. Given: DF ≅ EF FG bisects ∠DFE Prove: ∆DFG ≅∆EFG Please explain the anwser, because I don't know how to do this correctly.

Reasons:

1. Given

2. Given

3. Definition of bisector

4. Reflexive property

5. SAS Congruence

Step-by-step explanation:

This is quite easy to solve. All that you're expected to do is to complete the reason that justifies each statement given in the two-column proof.

Let's complete the proof as follows:

1. Statement:

1. Reason: Given

We know this statement is true because we are given in the question.

2. Statement: FG bisects <DFE

2. Reason: Given

We also know this because we are told so in the question, as shown in the diagram given.

3. Statement:

3. Reason: Definition of bisector

We know this because an angle bisector divides an angle into two equal halves. Therefore, the definition of bisector justifies why it was stated that

4. Statement:

Reason: Reflexive property.

5. Statement: ∆DFG EFG

5. Reason: SAS Congruence

Two sides (DF and FG) and an included angle (angle 1) of ∆DFG is congruent two corresponding sides (EF and FG) and an included angle (angle 2) of ∆EFG. Therefore, ∆DFG EFG by the Side-Angle-Side (SAS) Congruence Theorem.

answer: cos [   arcsin (3/5) - arccos (1/2) ] =

step-by-step explanation: × = 3/5 = 0.6--> x = 36.87 and x = 180 - 36.87 = 143.13 deg

cos y = 1/2 --> y = +- 60 deg a. cos (x - y) = cos (143.13 - 60) = cos 83,13  

=

0.12

b. cos (36.87 - 60) = cos (-23.23) = 0.92

where is the graph, sweetheart?

step-by-step explanation: