1. (Water freezes at 0°C. Give two examples
of two temperatures at which ice could
exist.

one temp that ice freezes or could exist would be 32°F and at -34°C

Step-by-step explanation:

he can buy 4lbs. of live bait and 1lbs of natural bait

step-by-step explanation:

5=812a+9+3

step 1: simplify both sides of the equation.

5=812a+9+3

5=(812a)+(9+3)(combine like terms)

5=812a+12

5=812a+12

step 2: flip the equation.

812a+12=5

step 3: subtract 12 from both sides.

812a+12−12=5−12

812a=−7

step 4: divide both sides by 812.

812a /812 = -7/812

a= -1/116

so the answer is

a=   -1/116