The number of miles driven by a truck driver falls between 300 and 700, and follows a uniform distribution. a. Find the probability that the truck driver goes more than 650 miles in a day.
b. Find the probability that the truck drivers goes between 400 and 650 miles in a day.
c. At least how many miles does the truck driver travel on the furthest 10% of days?

(A) 0.125 probability

(B) 0.625 probability

(C) 660 miles

Step-by-step explanation:

The distance driven by a truck driver daily, falls between 300miles and 700miles and follows a uniform distribution.

(A) The probability that the truck driver goes more than 650 miles a day is:

[700 - 650] / [700 - 300]  = 50/400  = 0.125

(B) The probability that the truck driver goes between 400 and 650 miles a day is:

[650 - 400] / [700 - 300]  = 250/400  = 0.625

(C) The minimum number of miles the truck driver travels on the furthest 10% of days is given thus:

10% of 400  = 40

Subtract this from the farthest distance;

700miles - 40miles  = 660miles

135 is your answer

step-by-step explanation:

try 180 times three then divide that number by 4 (sides) to get your answer. im glad to : )

don't know sorry bru

step-by-step explanation: