Mathematics, 12.11.2020 17:10 brittanyjacob8

10 Steve has 54 stamps in his collection of 13€,

294, and 45¢ stamps, totaling a value of $15.98.

If the number of 13¢ stamps is doubled, the

new total value of his stamp collection would

be $17.80. Find the number of each type of

stamp in his collection.

A) 14- 13€, 24 - 294, 16 - 45€

they felt like it

B) 16- 134, 25 - 294, 13- 45°

she lost a bet

C) 15 - 13€, 24-29€, 15 - 45°

she was bored

D) 15 - 13€, 25 - 294, 14- 454

she thought it was cool

E) 14- 13¢, 25 - 29%, 15 - 45°

it would be fun

Gina Wison II Ting Alpebra LC), 2016

Answers: 1

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Answer from: jaedenevan062907

This question was not written properly

Complete Question

Steve has 54 stamps in his collection of 13 cent, 29 cent, and 45 cent stamps, totaling a value of $15.98. If the number of 13 cent stamps is doubled, the new total value of his stamp collection would be $17.80. Find the number of each type of stamp in his collection.

a) The number of 13 cent = 14

b) The number of 29 cent = 24

c) The number of 45 cent = 16

Step-by-step explanation:

We are told he has 54 stamps in total.

These stamps are;13 cent, 29 cent, and 45 cent stamps.

Let's

Number of 13 cent = a

Number of 29 cent = b

Number of 45 cent = c

Hence,

a + b + c = 54 Equation 1

The total value of the 3 stamps are $15.98.

1 cent = $0.01

We have

0.13a + 0.29b + 0.45c= $15.98 Equation 2

We know from the question that:

13 cent stamps is doubled, the new total value of his stamp collection would be $17.80.

Therefore

2(0.13a) + 0.29b + 0.45c = 17.8

0.26a + 0.29b + 0.45c = 17.8 Equation 3

Combining Equation 2 and 3 together

0.13a + 0.29b + 0.45c= 15.98 Equation 2

0.26a + 0.29b + 0.45c = 17.8 Equation 3

We eliminate b and c by Subtracting Equation 3 from 3

0.13a = 1.82

a = 1.82/0.13

a = 14

a + b + c = 54 Equation 1

Since a = 14

14 + b + c = 54

b + c = 54 - 14

b + c = 40

c = 40 - b

Substitute 40 - b for c and 14 for a is Equation 2

0.13a + 0.29b + 0.45c= 15.98 Equation 2

0.13(14 ) + 0.29b + 0.45(40 - b) = 15.98

= 1.82 + 0.29b + 18 - 0.45b = 15.98

Collect like terms

1.82 + 18 - 15.98 = 0.45b - 0.29b

3.84 = 0.16b

b = 3.84/0.16

b = 24

Hence: Solving for c

a + b + c = 54 Equation 1

14 + 24 + c = 54

38 + c = 54

c = 54 - 38

c = 16

Therefore,

The number of 13 cent = 14

The number of 29 cent = 24

The number of 45 cent = 16

Answer from: Quest

The decimal expansion would be .27 repeated

Answer from: Quest

(6,1)(5,4)slope = (4 - 1) / (5 - 6) = 3/-1 = -3y = mx + bslope(m) = -3use either of ur , = 6 and y = 1now sub and find b, the y int1 = -3(6) + b1 = -18 + b1 + 18 = b19 = bso ur equation is : y = -3x + we need it in standard formy = -3x + 3x to both sides3x + y = 19 < == standard form

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