The area of a rectangle is 5/6 square foot. The width is 2/3 foot. How many times greater is the length than the width? Write your answer in simplest form.

15/8

Step-by-step explanation:

The area of a rectangle is given as 5/6 square foot.

The width is given as 2/3 foot

But area if a Rectangle = Lenght × width

A = Lenght x width

5/6= Lenght × 2/3

If we make Lenght subject of the formula we have

lenght= (5/6) / (2/3)

length = (5×3)/(6×2)

Lenght= 5/4

To calculate the number of times greater is the length than the width we take the ratio of Lenght and width

Lenght / width = (5/4) / (2/3)

= (5×3)/(4×2)

= 15/8

Hence the number of times greater is the length than the width is 15/8

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