Cheryl fenced in a rectangular kennel and used more fence to divide it into six equally sized sections for her dog i h is friends as shown. The length of each section is 2 feet more than 3 times its width.

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If the total amount of fence used for the kennel is 113 feet, what is the area of each section?

Enter the value of the answer in the first blank and enter the units in the second.

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The area of each section of the kennel is 33 square ft

Step-by-step explanation:

The given parameters for the fencing are;

The length of each section, L = 2 ft + The width, 3×W

The total amount of fencing = 113 feet

The The total perimeter of the kennel = 12·W + 7·L = 113

Were we are given L = 2 + 3·W

By substitution, we have;

12 × W + 7 × (2 + 3·W) = 113

33·W + 14 = 113

33·W  = 113 - 14 = 99

W = 99/33 = 3

W = 3 ft.

L = 2 + 3·W = 2 + 3 × 3 = 11

L = 11 ft.

The area of each section of the kennel, A = L × W = 3 × 11 = 33 square ft.

The area of each section of the kennel = 33 square ft.

took the test it's 94

complete the steps to find the area of the trapezoid.

area of rectangle = 256   square units

area of triangle 1 = 24  square units

area of triangle 2 = 16  square units

area of triangle 3 =   96 square units

area of trapezoid = 120  square units

step-by-step explanation: