A bee flies at 9 feet per second directly to a flower bed from its hive. The bee stays at the flowerbed for 15 minutes, and then flies directly back to the hive at 6 feet per second. It is away from the hive for a total of 18 minutes

Complete question is;

A bee flies at 9 feet per second directly to a flower bed from its hive. The bee stays at the flowerbed for 15 minutes, and then flies directly back to the hive at 6 feet per second. It is away from the hive for a total of 18 minutes.

a. What equation can you use to find the distance of the flowerbed from the hive?

b. How far is the flowerbed from the hive?

A) (d/9) + 900 + (d/6) = 1080

B) d = 648 ft

Step-by-step explanation:

A) We are told that A bee flies at 9 feet per second directly to a flower bed from its hive.

Time taken is given as;

t = distance/speed

If distance is d from the hive to the flower bird.

Then, t1 = d/9

The bee stays at the flowerbed for 15 minutes. Thus, time spent at the flowerbird in seconds is; t2 = 15 × 60 = 900 seconds.

We are told that the bee flew directly back to the hive at 6 feet per second.

Thus,time is;

t3 = d/6

Since total time spent away from hive is 18 minutes, then converting to seconds, we have; t = 18 × 60 = 1080 s

Thus;

(d/9) + 900 + (d/6) = 1080

B) Since we have derived;

(d/9) + 900 + (d/6) = 1080

Then we can find d.

Multiply through by 18 to get;

2d + (900 × 18) + 3d = 1080 × 18

2d + 16200 + 3d = 19440

5d = 19440 - 16200

5d = 3240

d = 3240/5

d = 648 ft

51

step-by-step explanation:

73-22=51 the   mass number minus the amount of protons gives you the amount of neutrons

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