Claire wants to build a patio outside her café. The rectangular space outside of Claire's café is three times as long as it is wide. The area of the space is 48 m2. Claire would like to build a patio with dimensions 3.5 m by 12.5 m in this space. Will it fit? Explain.

pls help

Step-by-step explanation:

It will fit in the space but it won't cover the entire space. the area is 48m2, but the patio in question will cover 43.75 of the 48m2. Also, it stated that the rectangular space is 3 times as long, and the patio is 3.57x as long as the width. So yes, it will fit, but it will not be a picture perfect fit, there will be some obscenities.

Step-by-step explanation:

Let length of space be lm and width be wm.

l = 3w --(1)

lw = 48 --(2)

sub (1) into (2):

3w(w) = 48

3w^2 = 48

w^2 = 16

w = ± 4 (rej -4 since w > 0)

when w = 4, l = 3(4) = 12

Since dimensions of the patio is 3.5m by 12.5m, and the dimensions of the space is 4m by 12m it does not fit

This is a topic known as simultaneous equations. If you would like to find out more / know when and how to use it, you can check out my Instagram page (learntionary)

step-by-step explanation:

step 1: solve one of the equations for one of the variables. let's solve the first equation for y:

step 2: substitute that equation into the other equation, and solve for x.

step 3: substitute x = 4 x = 4 x=4 into one of the original equations, and solve for y.