I really need help please

one solution at ( -1, 2 )

Step-by-step explanation:

-x + 2y =5

x + y = 1

You cross out the x’s then add 2y + y which will give you 3y. Add the 5 and 1 and you’ll get 6.

3y = 6

Divide 3 to both sides

y = 2

To get x you’ll use the first equation.

-x + 2y = 5

Replace the y with 2

-x + 2(2) = 5

-x + 4 = 5

Move the 4 to the other side, but you’ll need to flip it to negative. So 5 - 4.

-x = 1

Divide both sides by -1

x = -1

for the friend request.

when a figure, such as triangle (xyz) is reflected over the line y = x to create x'y'z' the x-coordinates and y-coordinates of the original image (pre-image) will be reversed for the image. (e.g., (x, y) > (y, x)) this means that the pre-image position of the x- and y-coordinates switch places which in turn provides a mirror like image of the original xyz.  

i notice that when i draw a line segment from x to x', that the points are parallel from each other -- they are exactly across from each other and do not intersect with any other points.  

yes, think i would see the same characteristic if you drew the line segment connecting y with the reflecting line and then y' with the reflecting line because of the essence of reflections. because it is a mirror image, each point was effected the same way which leads me to conclude that they same would apply to y and y'.