Question in pic. please help!

Arranging from longest (at top) to shortest (at bottom)

DF

EF

DE

Step-by-step explanation:

We need to place the sides of triangle DE, DF and EF from longest to shortest.

The triangle has longest side that is opposite to the largest angle

We know two angles < E= 61° , <F= 59° we need to find <D

Sum of angles of triangle = 180°

So, 61°+59°+<D=180°

120°+<D=180°

<D=180°-120°

<D=60°

So, the largest angle is <E= 61°

The longest side must be opposite to <E so, the side is DF

The second largest angle is <D=60° so, second side will be EF

The smallest angle is <F=59° so, third (shortest) side will be DE

Arranging from longest (at top) to shortest (at bottom)

DF

EF

DE

let's add {f(x)=x+1}f(x)=x+1 and {g(x)=2x}g(x)=2x together to make a new function.

f(x)+g(x) =(x+1)+(2x)=x+1+2x=3x+1

let's call this new function hh. so we have:

{h(x)}={f(x)}+{g(x)}{=3x+1}h(x)=f(x)+g(x)=3x+1

we can also evaluate combined functions for particular inputs. let's evaluate function hh above for x=2x=2. below are two ways of doing this.

method 1: substitute x=2x=2 into the combined function hh.

h(x)

h(2)

​    

=3x+1

=3(2)+1

=7

​ since h(x)=f(x)+g(x)h(x)=f(x)+g(x), we can also find h(2)h(2) by finding f(2) +g(2)f(2)+g(2).

first, let's find f(2)f(2):

f(x)

f(2)

​    

=x+1

=2+1

=3

​  

now, let's find g(2)g(2):

g(x)

g(2)

​    

=2x

=2⋅2

=4

​  

so f(2)+g(2)=3+4=\greend7f(2)+g(2)=3+4=7.

notice that substituting x =2x=2 directly into function hh and finding f(2) + g(2)f(2)+g(2) gave us the same answer!

answer: it's d

step-by-step explanation: