What is the density of 9 cm³ gold cube with 450 g in a mass?

Answer is 50g/cm^3

Step-by-step explanation:

soln,

Volume of the gold cube = 9 cm^3

Mass of the gold cube = 450 g

now,

density= mass/volume

=450 / 9

=50 g/cm^3

{Therefore, the density of the gold cube is 50 g/cm^3.}

554.4

step-by-step explanation:

44*12.6=544.4

fahrenheit

step-by-step explanation:

fahrenheit is more precise than celsius. the ambient temperature on most of the inhabited world ranges from -20 degrees fahrenheit to 110 degrees fahrenheit—a 130-degree range. on the celsius scale, that range is from -28.8 degrees to 43.3 degrees—a 72.1-degree range. this means that you can get a more exact measurement of the air temperature using fahrenheit because it uses almost twice the scale.