Please help, this chapter was on derivatives...

(3) Differentiating both sides of

with respect to x gives

Solve for dy/dx :

Then the slope of the tangent line to the curve at (1, 9) is

The equation of the tangent line would then be

y - 9 = -2/3 (x - 1)   ==>   y = -2/3 x + 29/3

(4) The slope of the tangent line to

at a point (x, y) on the curve is

When x = -1, we have a slope of 2/3, so

-(2a + 1)/(-1 - 2)² = 2/3

Solve for a :

-(2a + 1)/9 = 2/3

2a + 1 = -18/3 = -6

2a = -7

a = -7/2

(x, y)→(x − 8, y − 7)

step-by-step explanation:

enjoy!

the answer is a

step-by-step explanation: