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What is the equation of
y=x3
with the given transformations?

vertical stretch by a factor of 3, horizontal shift 4 units to the right, vertical shift 3 units down

The parent function is y = x³.

After a vertical stretch by a factor of 3, obtain

y = 3x³

After a horizontal shift 4 unit to the right, obtain

y = 3(x - 4)³

After a vertical shift 3 units down, obtain

y = 3(x - 4)³ - 3

  y = 3(x - 4)³ - 3

5x + 3y = - 4

step-by-step explanation:

the equation of a line in standard form is

ax + by = c ( a is a positive integer and b, c are integers )

express the line first of all in slope- intercept form

y = mx + c ( m is the slope and c the y-intercept )

to calculate m use the gradient formula

m = ( y₂ - y₁ ) / ( x₂ - x₁ )

with (x₁, y₁ ) = (7, - 3) and (x₂, y₂ ) = (4, - 8)

m = = -

y = - x + c ← is the partial equation

to find c substitute either of the 2 points into the partial equation

using (4, - 8 ), then

- 8 = - + c ⇒ c = -

y = - x - ← in slope-intercept form

multiply all terms by 3 to eliminate the fractions

3y = - 5x - 4 ( add 5x to both sides )

5x + 3y = - 4 ← in standard form