PLS HELP I WILL HELP BACK 15 POINTS WILL GIVE BRAINLIEST Write the equation of a polynomial, in standard form, that has: Zeros: 3, -2/5, 3i

leading coefficient of -5

 -5x^3 -13x^2 -6x + 15ix + 39ix + 18i

Step-by-step explanation:

An equation with zeros at these numbers could be put in form x = number.

So, (x-3) could be set to 0 to get x=3.

So, you can look at these "answers" they give you and work backward to get:

(x-3)(x+2/5)(x-3i)

Multiply first two together.

x^2+2/5x-3x-6/5

simplify

x^2 - 2 3/5x -6/5

Change first term to have same denominator by multiplying by "1" in the form of -5/-5

-5x^2/-5 - 13/5x -6/5

Divide all terms by 1/5 (which is the same as multiplying each term by 5)

(-5x^2 -13x -6)

Now multiply by (x-3i)

-5x^3 -13x^2 -6x + 15ix + 39ix + 18i

correct answer:

i^31 = -i

step-by-step explanation: