Write an equation in standard form of the line that passes through the given point and the given slope. (-9, -4); m = -1/3

First, we must determine b using slope-intercept form*, the given point, and the given slope.

Second, we need to set up the equation of the line in slope-intercept form.

Third, we convert the above equation to STANDARD FORM**.

We now have our equation:

*Slope-intercept form: y = mx + b

**Standard form: ax + by = c

it would be 6xy and -16xy.

answer: solve 5\cdot 2^x=2405⋅2  

x

=2405, dot, 2, start superscript, x, end superscript, equals, 240.

solution

to solve for xxx, we must first isolate the exponential part. to do this, divide both sides by 555 as shown below. we do not multiply the 555 and the 222 as this goes against the order of operations!

\begin{aligned} 5\cdot 2^x& =240 2^x& =48 \\ \end{aligned}  

5⋅2  

x

2  

x

​    

=240

=48

​

step-by-step explanation: