What methods could be used to solve the following quadratic equation x^2 +12-28=0

Step-by-step explanation:

x^2 +12x-28=0

x^2+(14-2)x-28=0

x^2+14x-2x-28=0

X(X+14)-2(X+14)=0

(X+14)(X-2) is the factor of this quadratic equation.

step-by-step explanation:

given that there are two triangles j'k'l' and jkl>

the former is got by dilating the second one.

when drawn on a grid, (graph paper) coordinates of vertices of first triangle is

(6,12)j, (9,6)k and (12,9)l

side jk has length = distance between j and k

=

side j'k'=distance between j' and k'

=

ie j'k'l' has sides 1/3 of that of corresponding sides of jkl.

hence scale factor of 1/3 is used to get j'k'l'from jkl

step-by-step explanation:

consider an orange peel: if you want to try and lay it flat, you have to stretch it, we know exactly how things are being stretched or squashed at any given point. we have many different map projections because each has different patterns of some projections can even preserve certain features of the earth without