Clarice graphed the amount of money in her savings account during the past six months on the line graph. A line graph titled Savings has months on the x-axis and Money on the y-axis. Month 1 was 90 dollars, month 2 was 110 dollars, month 3 was 80 dollars, month 4 was 50 dollars, month 5 was 90 dollars, month 6 was 110 dollars. Between which two months did the greatest change in the amount of money in the account occur? months 2 and 3 months 3 and 4 months 4 and 5 months 5 and 6

among us code WKRFCKC

Step-by-step explanation:

code usss

The answer to your question is months 4 and 5

Step-by-step explanation:

To solve this problem get the slope of the different intervals

2-3 Months     m = (80 - 110) / (3 - 2)

                             = -30 / 1

                             = -30

3 - 4 Months    m = (50 - 80) / (4 - 1)

                             = -30 / 1

                             = -30

4 - 5 Months    m = (90 - 50) / (5 - 1)

                              = 40 / 1

                              = 40

5 -6 Months       m = (110- 90) / (6 - 5)

                              = 20 / 1

                             = 20

Conclusion

The greatest change was between months 4 and 5

if the eqn of the parabola is f(x) = (x-4)(x+2), we need to mult. this out to find the coordinates of the vertex.

then f(x) = x^2 + 2x - 4x - 8, and f(x) = x^2 - 2x - 8.

one way in which you can find the vertex is to calculate x = -b / (2a).   here, that comes to

        )

x = = 1.   f(1) = 1^2 - 2(1) - 8 = - 9.   vertex is at (1, -9).

        2(1) 

find another point on the curve:   let x=0, for which y=-8.   then (0, -8) is on the curve.   plot the vertex and this point and draw a smooth parabola thru both.

hope this