The area of a square is s2, where s is the side length. Suppose you have three squares. One square has side length 9 feet. Another square has side length 6 feet. The third square has side length . Is the sum of the areas of the two smaller squares equal to the area of the large square? Use pencil and paper. Explain your answer. Then describe three squares for which you would give the opposite answer for the same question.

The answer is 4 points

The coefficient, 5 represents the length in relation to the problem.

Ok here we go ..there are plenty of ways to solve such math problems but we will go for the smartest and easiest ..5x+2y=7  -2x+6y=9we rearrange them into the following ..by multiplying the 1st equation by 2 it becomes 10x + 4y = 14we rearrange it and so it becomes 10x = 14 - 4yas for the second equation we multiply it by 5 and rearrange it so it becomes as to the following ..-10x + 30y = 45rearranging so 10x = 30y -45now 10x equals both 14 - 4y and 30y -45so   14 - 4y = 30y -4531 = 26yy= 31/26 = 1.19 or around 1.2so by now we can calculate x easily as  -2x+6y=9so 2x = 6y -9 = 6 * 31/26 - 9 = -1.84  then x = - 0.92 or around -0.9best luck!

Hi the answer is b
hope that