Applicants to a psychology department have normally distributed GRE scores with a mean, LaTeX: \muμ, of 544 and a standard deviation, LaTeX: \sigmaÏ, of 103. What percentage of applicants scored between 500 and 700? Round to the nearest percent. A. -24% B. 78% C. 2296 D. 24% E. 5%

The probability is P(500 < X  < 700 ) =  0.60044

Step-by-step explanation:

From the question we are told that

    The mean is  

     The standard deviation is  

Generally the percentage of applicant that scored between 500 and 700 is mathematically represented as

=>  

Generally from the z-table, the area under the normal curve to the left corresponding to    1.5146 and     -0.4272  is

  P(  Z<  1.5146 )  =  0.93506

   P ( Z <   -0.4272 ) = 0.33462

So

       P(500 < X  < 700 ) =  0.93506 -  0.33462

=>    P(500 < X  < 700 ) =  0.60044

5x+40

5(x + 8)

7x - 49

7(x - 7)

18x + 9

9(2x + 1)

15x - 10

5(3x - 2)

step-by-step explanation:

for number one all you have to do is factor 5 out of 5x + 40

for number 2 factor 7 out of 7x - 49

for number three factor 9 out of 18x + 9

for number four factor 5 out of 15x - 10