A bag contains 6 red apples and 6 yellow apples. A sample of 3 apples is drawn. Find the probability that the sample contains more red than yellow apples

21/44

Step-by-step explanation:

Given that:

Bag contains :

6 red apples

6 yellow apples

Number of samples drawn = 3

Probability that sample contains more red than yellow :

Then from the three samples, red = 2 and yellow = 1 or red for all 3

Prob of RRR = (6/12)(5/11)(4/10)= 120 / 1320

Prob RRY = (6/12)(5/11)(6/10)= 150/1320

Prob RYR is (6/12)(6/11)(5/10)= 180/1320

Prob YRR is (6/12)(6/11)(5/10)=180/1320

120/1320 + 150/1320 + 180/1320 +. 180/1320 = 630/1320 =126/264 = 42/88 = 21/44

$9.89

step-by-step explanation:

9.90 = p x .06 x .25 (3/12 changed to a decimal)

9.90 = p x 0.015

9.90 - 0.015 = p

9.89 = p