Colton bounces a ball 3.268 feet infront of his feet. The path of the ball from the time it hits the ground until it lands on the floor is represented by

here is the complete and correct question. Colton bounces a ball 3.268 feet in front of his feet. The path of

the ball from the time it hits the ground until it lands on the floor is represented by

f(x) =-4(x - 5)2 + 12

Assuming that Colton's feet are located at the origin, (0, 0), what is the maximum height of the ball (in feet)?

12ft

step by step explanation:

This equation has been written in vertex form, and it has its vertex at (5, 12). Because the scale factor is not positive, it has a negative value, the graph for the question is going to open downward, such that the vertex,

that is the maximum height is 12 ft.

we have The equation of a parabola with vertex (h, k) to be

f(x) = a(x -h)² + k

when put in Comparison to your question function, we get that

a=-4

h=5

k=12

so the vertex (h, k) = (5, 12).

the ratio of balloons to tables is 5: 2 and the constant variation is 5.

the equation is y=5x