The coordinates of three vertices of a square are (1, –1), (6, –1), and (6, 4). Fill in each blank to make the statement true. What is the area of the square?

Step-by-step explanation:

Given the coordinates of three vertices of a square as A(1, –1), B(6, –1), and C(6, 4). The area of the square is expressed as;

A = L² where;

L is the one of the side length of the square.

Note that all the sides of a square are equal;

To get one of the side length, we will find the distance between any two of the coordinates points. Using the coordinates A(1, –1), B(6, –1)

L = AB = √(x2-x1)²+(y2-y1)²

L = √(6-1)²+(-1-(-1))²

L = √5²+0²

L = √25

L = 5

Area of the square = 5²

Area of the square = 25units²

Hence the area of the square is 25units²

i suppose it should be (y=2x-5)

step-by-step explanation:

step-by-step explanation: