The accompanying data represent the miles per gallon of a random sample of cars with a three-cylinder, 1.0 liter engine. (a) compute the z-score corresponding to the individual who obtained 37.8 miles per gallon. interpret this result.
(b) determine the quartiles.
(c) compute and interpret the interquartile range, iqr.
(d) determine the lower and upper fences. are there anyoutliers?
31.5 36.0 37.8 38.5 40.1 42.2
34.2 36.2 38.1 38.7 40.6 42.5
34.7 37.3 38.2 39.5 41.4 43.4
35.6 37.6 38.4 39.6 41.7 49.3
the z-score corresponding to the individual is
and indicates that the data value is
standard deviation(s) the
the table is for the entire problem.

A.) - 0.2992

B.) Q1 = 36.75

Q2 = 38.45

Q3 = 41

C.) IQR = 4.25

D.) LOWER FENCE = 30.375

UPPER FENCE = 47.375

Yes, 49.3

Step-by-step explanation:

Given the data:

Arranged data in ascending order :

31.5, 34.2, 34.7, 35.6, 36.0, 36.2, 37.3, 37.6, 37.8, 38.1, 38.2, 38.4, 38.5, 38.7, 39.5, 39.6, 40.1, 40.6, 41.4, 41.7, 42.2, 42.5, 43.4, 49.3

Using calculator to save computation time :

Population mean (μ) = 38.88

Standard deviation (s) = 3.61

A.) The zscore for individual who obtained 37.8 miles per gallon :

Standardized score formula :

Z = (Score(x) - mean) / standard deviation

Z = (37.8 - 38.88) / 3.61

Z = - 1.08 / 3.61

Z = - 0.29916

Z = - 0.2992

B) The quartile ;

Lower quartile (Q1) :

1/4(n +1)th term

n = sample size = 24

1/4(24 + 1)

= 1/4(25) = 6.25th term

(6th + 7th) =(36.2 + 37.3) = 73.5/2 = 36.75

Upper quartile (Q3) :

3/4(24 +1) = 3/4(25) = 18.75th term

(18th + 19th) = (40.6 + 41.4) = 82/2 = 41

Median (Q2) :

1/2(24 +1) = 1/2(25) = 12.50th term

(12th + 13th) = (38.4 + 38.5) = 76.9/2 = 38.45

C.) interquartile range :

Q3 - Q1 = (41 - 36.75) = 4.25

D.) OUTLIER

LOWER : Q1 - 1.5(IQR) = 36.75 - 1.5(4.25) = 30.375 ; values less than 30.375

UPPER : Q3 + 1.5(IQR) = 41 + 1.5(4.25) = 47.375 ; values greater than. 47.375

rick has $1400 and sally has $1500

step-by-step explanation:

to find amount of money rick has after 10 years :

principal = $1000 , time = 10 years , rate = 4% annually

to find amount of money sally has after 10 years :

her friend gives to pay her $50 per year, therefore money she has after 10 years = 50 × 10 = $500

also, sally gets $1000 after 10 years,

therefore, total amount of money sally has after 10 years = 500 + 1000 = $1500

so, after 10 years : rick has $1400 and sally has $1500

did you get the answer?