How many liters each of a 45% acid solution and a 70% acid solution must be used to produce 50 liters of a 65% acid solution? (Round to two decimal places if necessary.)

The number of liters of the 45% acid solution = 10 liters

The number of liters of the 70% acid solution is = 40 liters

Step-by-step explanation:

How many liters each of a 45% acid solution and a 70% acid solution must be used to produce 50 liters of a 65% acid solution? (Round to two decimal places if necessary.)

Let x be the number of liters of the 45% acid solution

The number of liters of the 70% acid solution is y

x + y = 50

x = 50 - y

Also

How many liters each of a 45% acid solution and a 70% acid solution must be used to produce 50 liters of a 65% acid solution?

We have:

45% × x + 70% × y = 65% × 50

0.45x + 0.70y = 0.65 × 50

0.45x + 0.70y = 32.5

We substitute x = 50 - y in the equation

0.45(50 - y) + 0.70y = 32.5

= 22.5 - 0.45y + 0.70y = 32.5

= - 0.45y + 0.70y = 32.5 - 22.5

= 0.25y = 10

Divide both sides by 0.25

= y = 10/0.25

y = 40 liters

x = 50 - y

x = 50 - 40

x = 10 liters

Hence,

The number of liters of the 45% acid solution = 10 liters

The number of liters of the 70% acid solution is = 40 liters

i need the table so i can see

step-by-step explanation:

8(-10x+3.5y-7)

8×-10x + 8×3.5y + 8×-7

-80x + 28y - 56

therefore

-80x+28y-56 is the correct answer