A small kite starts 3.7meters off the ground and rises at 6.2 meters per second. A large kite starts at 20.65 meters off the ground and drops at a rate of 5.1 meters per second. After how many seconds are the kites at the same height? Write and solve an equation.

The kites are  at the same height at 15.41s

Step-by-step explanation:

Step 1

Let t represent the time in seconds.

The equation that represents when both small and large kite are at the same height is given as

3.7 + 6.2t =20.65 +5.1t

Step 2 Solving

3.7 + 6.2t =20.65 +5.1t

Taking like terms  and subtracting

6.2t-5.1t  = 20.65- 3.7

1.1t =16.95

t = 16.95/1.1

t=15.41s

The kites are  at the same height at 15.41s

c

step-by-step explanation:

it isn't d, because the interquartile range is from 27-57. and the interquartile range is basically half the data, it's pretty obvious.

it isn't b, because like i said earlier, the interquartile range is from 27-57. 57-27 is 30. the real range has to be longer

not a either. although it looks like it, 3/4 of the data is not greater than 27. but if c is wrong than this should be correct

the correct answer is c, because 13 is the point in which the plot starts

hello :

70y^8 + 30y^6 = 2 ( 35 y^8 + 15y^6)

the lenght is : 35 y^8

the width is : 15y^6