An observer (O) is located 500 feet from a school (S). The observer notices a bird (B) flying at a 39° angle of elevation from his line of sight. How high is the bird flying over
the school? You must show all work and calculations to receive full credit. (10 points)
B
h
39°
0
s
500 feet

h = 404.89 feet

Step-by-step explanation:

An observer (O) is located 500 feet from a school (S).

The angle of elevation from his line of sight is 39°.

We need to find how high is the bird flying over  the school. Let BS = h. We can find it using trigonometry as follows :

P is perpendicular and B is base

P = BS = h, B = 500 feet and

So,

So, the bird is at a height of 404.89 feet,

mr. flanders’ class sold 47 doughnuts and   mr. rodriquez’s class sold 38 cartons of milk

step-by-step explanation:

let x be the number of doughnuts sold by mr. flanders’ class and y be the number of cartons sold by mr. rodriquez’s class.

1. together, the classes sold 85 items, then

x+y=85.

2. both classes earn earned $104.49 for their school. if doughnuts were sold for $1.35 each, then x doughnuts costed $1.35x. if cartons of milk were sold for $1.08 each, then y cartons costed $1.08y. hence,

1.35x+1.08y=104.49.

3. solve the system of two equations:

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