Which of these triangle pairs can be mapped to each other using a single reflection? Triangles F E G and F G L are congruent. Triangle F E G is reflected across line F G to form triangle F G L. Triangles F E G and G L M are congruent. Triangle E F G is rotated about point G to form triangle G L M. Triangles F E G and L M N are congruent. Triangle F E G is shifted down and to the right to form triangle L M N. Triangles L M N and E F G are congruent. Triangle F E G is reflected across a line to form triangle L M N. Triangle L M N is also slightly higher and to the right of triangle E F G.

step-by-step explanation:

given that there are two triangles j'k'l' and jkl>

the former is got by dilating the second one.

when drawn on a grid, (graph paper) coordinates of vertices of first triangle is

(6,12)j, (9,6)k and (12,9)l

side jk has length = distance between j and k

=

side j'k'=distance between j' and k'

=

ie j'k'l' has sides 1/3 of that of corresponding sides of jkl.

hence scale factor of 1/3 is used to get j'k'l'from jkl

answer: b

step-by-step explanation:

explanation:

step-by-step explanation:

hello from mrbilldoesmath!

answer:   x^2 + y^2 = 1024

discussion:

the equation of a circle with center (h,k) and radius "r" is

(x-h)^2 + (y-k)^2 = r^2.

in our case

(x-0)^2 + (y-0) ^2 = 32^2 = 1024

you,

mrb