Write an equation of the line that passes through (7, 10) and is perpendicular to the line y = 1x – 9.

y = - x + 17

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

y = x - 9 ← is in slope intercept form

with slope m = 1

Given a line with slope m then the slope of a line perpendicular to it is

= - = - = - 1 , thus

y = - x + c ← is the partial equation

To find c substitute (7, 10) into the partial equation

10 = - 7 + c ⇒ c = 10 + 7 = 17

y = - x + 17 ← equation of perpendicular line

answer: h

step-by-step explanation:

g(x) = 3*(8(3^(x−2))+2)

g(x) = 24 (3^(x-2) )+6

the factor is 2

step-by-step explanation:

let f(x)=8(3^(x−2)+2)

to stretch a graph by 3, it would be 3f(x)

g(x) =3f(x)

g(x) = 3*(8(3^(x−2))+2)

g(x) = 24 (3^(x-2) )+6

x     −2     0     2     4     6

f(x) 1/64 1/16   1/4     1     4

1/64 * z * z = 1/16

i multiplies by z twice because it its 2 steps from -2 to 0

1/64 z^2 = 1/16

multiply by 64 to clear the fraction on the left side

1/4 * 64 z^2 =1/16 *64

z^2 = 4

take the square root of each side

sqrt(z^2) = ±sqrt(4)

z = ±2  

we are multiplying by 2 each time.