PLEASE HEL(BRAINLIEST FOR RIGHT ANSWER) What is the rectangular form of r = 8 sin(θ)?

(x − 4)2 + y2 = 16
(x + 4)2 + y2 = 16
x2 + (y − 4)2 = 16
x2 + (y + 4)2 = 16

The relation between polar and Cartesian coordinates are

r2=x2+y2

tan

θ

=

y

x

,

x

=

r

cos

θ

,

y

=

r

sin

θ

r

=

8

sin

θ

∴

r

⋅

r

=

r

⋅

8

sin

θ

or

r

2

=

8

r

sin

θ

∴

x

2

+

y

2

=

8

y

or

x

2

+

y

2

−

8

y

=

0

or

x

2

+

y

2

−

8

y

+

16

=

16

or

x

2

+

(

y

−

4

)

2

=

4

2

Rectangular form is

x2+(y-4)2=42

graph{x^2+(y-4)^2=16 [-20, 20, -10, 10

Step-by-step explanation:

i created it that way so yall will take a longer time to answer

70,000 + 6,000 + 800 + 30

step-by-step explanation: