What is the factored form of x3 + 216? A.
(x − 6)(x2 + 6x + 36)
B.
(x + 6)(x2 − 6x + 36)
C.
(x + 6)(x2 − 12x + 36)
D.
(x + 6)(x2 + 12x + 36)

The answer is letter B.

Solution:

(x+6)(x2−6x+36)

=(x+6)(x2+−6x+36)

=(x)(x2)+(x)(−6x)+(x)(36)+(6)(x2)+(6)(−6x)+(6)(36)

=x³−6x2+36x+6x2−36x+216

=x³+216

arithmetic sequence

step-by-step explanation:

given that a sequence has terms as

19, 15, 11,

this is represented on a graph

the pattern indicates that the sequence is an arithmetic sequence with i term

a=19 and common difference d =-4

any general term

thus the sequence is reduced by 4 for each successive term starting from 1 and nth term is

24-5n.

first negative term would start after 5th term

5th term =24-25< 0

from 5th term onwards the sequence would be negative.