2x - 5y + 3z = 27 4x + 3y - 7z=-37
x - 2y + 5z = 30
I need help solving this with cramers rule

Step-by-step explanation: answer {x,y,z} = {1,-2,5}

/ Solve equation [3] for the variable x

[3] x = 2y - 5z + 30

// Plug this in for variable x in equation [1]

[1] 2•(2y-5z+30) - 5y + 3z = 27

[1] - y - 7z = -33

// Plug this in for variable x in equation [2]

[2] 4•(2y-5z+30) + 3y - 7z = -37

[2] 11y - 27z = -157

// Solve equation [1] for the variable y

[1] y = -7z + 33

// Plug this in for variable y in equation [2]

[2] 11•(-7z+33) - 27z = -157

[2] - 104z = -520

// Solve equation [2] for the variable z

[2] 104z = 520

[2] z = 5

// By now we know this much :

x = 2y-5z+30

y = -7z+33

z = 5

// Use the z value to solve for y

y = -7(5)+33 = -2

// Use the y and z values to solve for x

x = 2(-2)-5(5)+30 = 1

the median here is 25. your lowest value is 14 and highest value is 48. to find the third quartile, find the medium number in between 25 and 48 which would be 42 i believe.

b

step-by-step explanation:

the word superfluous means unnecessary