In triangle NQL, point S is the centroid, NS = (x + 10) feet, and SR = (x + 3) feet. Triangle N Q L has centroid S. Lines are drawn from each point to the midpoint of the opposite side to form line segments N R, Q M, and L P. The length of line segment N S is x + 10 and the length of line segment S R is x + 3.

What is RS?

4 feet
7 feet
10 feet
14 feet

B. 7 feet

Step-by-step explanation:

Given:

NS = (x + 10) ft

SR = (x + 3) ft

Required:

RS

SOLUTION:

Based in the centroid theorem, the centroid, S will divide the median, line segment NR, into NS and SR, such that NS : SR = 2 : 1.

Therefore:

NS = 2(SR)

x + 10 = 2(x + 3) (substitution)

Solve for x

x + 10 = 2x + 6

Collect like terms

x - 2x = -10 + 6

-x = -4

divide both sides by -1

x = 4

SR = (x + 3) ft (SR is same as RS)

Plug in the value of x

SR = (4 + 3) ft

SR = RS = 7 ft

(x3 + 6x2 + 2x - 6) • (x - 1)

step-by-step explanation:

polynomial long division :

3.2     polynomial long division

dividing :   x4+5x3-4x2-8x+6

                              ("dividend")

by         :     x-1     ("divisor")

dividend     x4   +   5x3   -   4x2   -   8x   +   6

- divisor   * x3     x4   -   x3            

remainder         6x3   -   4x2   -   8x   +   6

- divisor   * 6x2         6x3   -   6x2        

remainder             2x2   -   8x   +   6

- divisor   * 2x1             2x2   -   2x    

remainder               -   6x   +   6

- divisor   * -6x0               -   6x   +   6

remainder                     0

quotient :   x3+6x2+2x-6   remainder:   0