In triangle NQL, point S is the centroid, NS = (x + 10) feet, and SR = (x + 3) feet. Triangle N Q L has centroid S. Lines are drawn from each point to the midpoint of the opposite side to form line segments N R, Q M, and L P. The length of line segment N S is x + 10 and the length of line segment S R is x + 3.

What is RS?

4 feet
7 feet
10 feet
14 feet

B. 7 feet

Step-by-step explanation:

Given:

NS = (x + 10) ft

SR = (x + 3) ft

Required:

RS

SOLUTION:

Based in the centroid theorem, the centroid, S will divide the median, line segment NR, into NS and SR, such that NS : SR = 2 : 1.

Therefore:

NS = 2(SR)

x + 10 = 2(x + 3) (substitution)

Solve for x

x + 10 = 2x + 6

Collect like terms

x - 2x = -10 + 6

-x = -4

divide both sides by -1

x = 4

SR = (x + 3) ft (SR is same as RS)

Plug in the value of x

SR = (4 + 3) ft

SR = RS = 7 ft

i = 2 / - 5

step-by-step explanation:

evaluation of ( 2 - 4 ) ( p + q ) when p = 2 and q = 5 i, by putting values of p and q,