Let X be the winnings of a gambler . Suppose that P{x=0}=1/3 , P{x=1}=P{x=-1} =13/55 , P{x=2}=P{x=-2} =1/11 , P{x=3}=P{x=-3} =1/165 ; Compute the conditional probabilty that the gamble wins i, i = 1,2,3, given that he wins a positive amount.

3

Step-by-step explanation:

answer: the answer to your question is parallel

c. y = 1/4 x + 5

step-by-step explanation:

first, put the equation of the line on the graph into slope-intercept form

(y = mx + b):   y = -4x + 8

second, a perpendicular line has to have "an opposite/reciprocal slope" to the original slope. so, find the "m" value in your original equation (it's -4, right? )

original slope: m = -4   perpendicular slope: change the sign to its opposite and find the reciprocal ("flip" the number)

new slope is now positive (b/c the original slope was negative 4), and it's 1/4 (not the original slope of 4 or 4/1)