A jar contains 20 yellow jellybeans, 20 orange jellybeans, 20 red jellybeans and 20 green jellybeans. Required:
a. In how many ways can you put all the jellybeans in a row?
b. How many ways are there to select a handful of 20 jellybeans?
c. How many ways are there to select a handful of 20 jellybeans that contains at least 3 red?
d. How many ways are there to select a handful of 20 jellybeans that contains at least 3 red and at most 2 orange?

A)

B)

C)

=

D)

=

Step-by-step explanation:

A) How many ways can you put all Jellybeans in a row

Total number of Jellybeans = 80

The first jellybeans = 20 yellow , second is 20 orange jellybeans , third is 20 red jellybeans , fourth is 20 green jellybeans

Therefore the number of ways the Jellybeans can be put in a row is :

B) How many ways are there to select a handful of 20 jellybeans

lets assume:

yellow jellybeans = a , orange jellybeans = b , red jellybeans = c , green jellybeans = d

a + b + c + d = 20

This is the number Non-negative integer solutions

=

C) This is also the number of Non-negative integer solutions but in this case the value of C ≥ 3

hence the number of ways to select a handful of 20 jellybeans that contains at least 3 red

=

D) In this case the value of C ≥ 3 and B ≤ 2

Hence the number of ways to select a handful of 20 jellybeans that contains at least 3 red and at most 2 orange

=

answer: the first one

step-by-step explanation: use a calculator and divide the minutes by the dollars.

7! = 7×6×5×4×3×2

3! = 3× 2

as 7! is multiple of 3! because 7! contains 3! that is 3× 2 as factor

so 7! /(3! ) = 7× 6× 5× 4

= 42 × 20

= 840

its b) 840✌✌✌

dhruv⭐