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Mathematics, 09.11.2020 16:50 furryartist554

X 0 1 2 3 4 5 P(X) 0.10 0.20 0.45 0.15 0.05 0.05 Using the above information, the standard deviation of the number of accidents is A. 1.18 B. 1.4 C. 1.81 D. 1.96

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X 0 1 2 3 4 5 P(X) 0.10 0.20 0.45 0.15 0.05 0.05 Using the above information, the standard deviation...
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