In ΔJKL, \overline{JL} JL is extended through point L to point M, \text{m}\angle JKL = (3x-16)^{\circ}m∠JKL=(3x−16) ∘ , \text{m}\angle LJK = (2x+15)^{\circ}m∠LJK=(2x+15) ∘ , and \text{m}\angle KLM = (8x-19)^{\circ}m∠KLM=(8x−19) ∘ . Find \text{m}\angle LJK. m∠LJK.

idk

step-by-step explanation:

idk what the heck he answer is, i’m just putting this here so i finish my account

1. 180°. the sum of the interior angles of a triangle is 180°, for the equilateral triangle that it has three equals side is 60°+60°+60°=180°.

2. 60°. each interior angle of a equilateral triangle is 60°

3. 120°. the measure of ∠m is 120°, the sum of the angles ∠m and ∠n is equal to 180°. so, in order to find the measure of ∠m, we have ∠m+∠n=180° > ∠m=180°-∠n > ∠m=180°-60°=120°.

4. 360°. the sum of the exterior angles of an equilateral triangle is ∠m+∠r+∠x=120°+120°+120°=360°. the exterior angles of any triangle always add 360°.

i think da answer is

d.square root of 3