at what point in the first quadrant does the line with equation y=×+4 intersect the circle with the radius 5 and center (0,4)

x=3.536, y=7.356

Step-by-step explanation:

The point of intersection can be found out be equating the equations x^2+(y-4)^2=25 and y=x+4. Solving it we will get x=3.536, y=7.356

check above link.

graphically?   well, you graph them both, the solutions is where they both intersect each other, since there are two solutions, meaning they will meet twice, or namely the linear will run into the quadratic curve twice, and where they meet, those x,y coordinates are the solutions to the system.

you need to give us more information since we can't answer