Solve the inequality 8y - 3(y - 2)< 2y + 4(2y + 4) write solution in interval notation

y>-2

Step-by-step explanation:

8y-3(y-2) < 2y+4(2y+4)

8y-3y+6 < 2y+8y+16

6-16<2y+8y-8y+3y

-10<5y

y>-2

(−∞,−2)

Step-by-step explanation:

Start by simplifying each side as much as possible by distributing and combining like terms to get

8y−3(y−2)8y−3y+65y+6>2y+4(2y+4)>2y+8y+16>10y+16

Subtract 10y from both sides to collect the variables on the left, then subtract 6 from both sides to collect all the constants on the right.

5y+65y+6−10y−5y+6−5y+6−6−5y>10y+16>10y+16−10y>16>16−6>10

Divide each side by −5 to solve for y. Since −5<0, the inequality changes direction.

−5y−5y−5y>10<10−5<−2

In interval notation, we write this as (−∞,−2).

its d. the first coordintaes are 10,32

step-by-step explanation:

x=6 and x=3

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