Rewrite the function f(x)=3(x+1)^2-2 in the form f(x)=ax^2+bx+c im so stuck on these problems thanks so much for the help

f(x) = 3x² + 6x + 1

General Formulas and Concepts:

Step-by-step explanation:

Step 1: Define function

f(x) = 3(x + 1)² - 2

Step 2: Find Standard Form

Step-by-step explanation:

f(x)=3(x+1)^2-2

= 3 [x^2 + 2x + 1 ] -2

=3x^2 + 6x +3-2

=3x^2 + 6x + 1

f(x)=ax^2+bx+c

ax^2+bx+c = 3x^2 + 6x + 1

a = 3

b = 6

c = 1

the answer

b. they are parallel and will never intersect.

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step-by-step explanation: