The sum of a three-digit number and a one-digit number is 160. the product of the two number is 624. what are the two numbers?

Here is the legit way to solve
the numbers are x and y
x+y=160
product is 624
xy=624

x+y=160
minus x from both sides
y=160-x
sub that for y
x(160-x)=624
distribute
160x-x^2=624
multiply both sides by -1
x^2-160x=-624
add 624 both sides
x^2-160x+624=0

use quadratic formula
for
ax^2+bx+c=0
x=

a=1
b=-160
c=624

x=
x=
x=
x=(312)/2 or 8/2
x=156 or 4
those are the 2 numbers

the way that doesn't require as much work is
there are only 9 possible one digit numbers
it cannot have decimpals when divided
trial and error
624/1=624, 624+1=625, not 160
624/2=312, 312+2=314, not 160
624/3=208, 208+3=211, not 160
624/4=156, 156+4=160, great

anyway, the numbers are 4 and 156

The answer is

Iknow one of the answers is a and maybe b but not 100% sure about b