A bag contains x yellow balls, 2x + 1 green balls and 3x + 2 black balls. There are 39 balls in the bag. Find the numbers of yellow, green and black balls in the bag

no. of yellow balls = x = 6

no. of green balls= 2x+1= 2×6+1= 13

no of black balls= 3x+2= 3×6+2= 20

Step-by-step explanation:

we can write it as

x+ 2x+1 + 3x+ 2 = 39

6x+3=39

6x=39-3

6x= 36

x= 36/6

x= 6

no. of yellow balls = x = 6

no. of green balls= 2x+1= 2×6+1= 13

no of black balls= 3x+2= 3×6+2= 20

step-by-step explanation:

always plug in x. in this case, x equals 4.

i'm going to first solve 4(2+3x)

1) 4(2+3(4)) use pemdas to solve.

i'm going to multiply whats in the parenthesis first, so 3 times 4=12.

2)4 (2+12) i'm then going to multiply 4 by both numbers in the parenthesis (because multiplying comes before adding)

4 times 2= 8.   4 times 12= 48

4) (8+48)= 56 (answer)

i'm then going to solve 8+12x and plug in 4 for x.

1) 8 +12(4)

multiplying comes before adding, so i'm gonna multiply 12 and 4.

12 times 4= 48.

2) 8+48=56

both equal the same!