A line passes through the point (4, –6) and has a slope of Negative three-fourths. Which is the equation of the line? y = negative three-fourths x minus 3
y = negative three-fourths x minus 6
y = negative 3 x minus three-fourths
y = negative 6 x minus three-fourths

Option A

Step-by-step explanation:

The equation of line is

Solution:

Given that line passes through the point (4, –6) and has a slope of Negative three-fourths

Given point is (x, y) = (4, -6)

The equation of line passing through point (x, y) and slope "m" is given as:

y = mx + c eqn 1

Where "m" is the slope of line and "c" is the y - intercept

Substitute (x, y) = (4, -6) and  in eqn 1

The required equation of line is given as:

Thus the equation of line is found

21/58.

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