I NEED HELP ASAP
Answer these two questions I am confused. Number 17 and 18.

Step-by-step explanation:

Question 17

y-y1 = m (x-x1 )

so basically you plug in the (x,y) to y1 and x1 place

Remeber always times it by -1

so answer would be

y-2 = -1/3 (x+4)

Question 18

Pretend its 3x+2y =8

you need to find x or y first im going to find y first

so

- 2y = -3x +8

divide by 2 to isolate y

y = -3/2x - 4

plug it back into the equation

3x + 2(-3/2x) - 4

the x will cancel

so y= -4

Then

plug in the -4 in place of y

SO the Answer is YES because y is horizontal there is -4 = there will be (-3, -4)!

answer: ratio of volume of cone (with 3 times the height and equal diameter) to volume of cylinder is 2 to 1. the value of π is not used.

step-by-step explanation:

radius is diameter/2 = 4.

area of circle is π r^2.

volume of cylinder is height × area of base = hπr^2 = 3(4^2) π = 48π cubic inches.

not knowing the formula for volume of cone, i calculate it using calculus (which is for calculating things).

volume of cone is integral 0 to h area(y) dy. area(y) is π r(y)^2. r(y) runs r to zero as y runs zero to h, r(0) = r, r(h) = 0.

r(y) = r - r/h y

area(y) = π (r - r/h y)^2 = π (r^2 - 2r^2y/h + r^2y^2/h^2) = π r^2(1-2y/h+y^2/h^2)

antiderivative area(y) = π r^2 (y-y^2/h+y^3/(3h^2))

integral 0 to h = π r^2(h-h^2/h+h^3/(3h^2) - (0)) = π r^2(h - h + h/3) = π r^2(h/3) = π/3 r^2 h

volume of this cone is π/3(4^2)18 cubic inches.

= 6 16 π = 96π cubic inches.

cone has twice the volume, 96/48.

cone height is 6 times the cylinder.

ratio of volume formula: π r^2 cancels.

cone over cylinder ratio is 6h/3 to h, 2 to 1.