In the right ∆ABC, BL is an angle bisector. If LB = 1.2 in and LC = 0.6 in. Find: - The distance from L to AB.

- m∠ABC

Distance of L from AB = 0.6 in.

m∠ABC = 60°

Step-by-step explanation:

Given:

LB = 1.2 in

LC = 0.6 in

We have to find the distance of point L to AB or length of LD.

From right triangle ΔBCL,

Sin(∠LBC) =

                 =

                 =

                 =

m∠LBC = 30° [Since ∠LBC is an acute angle]

Since, ∠LBC ≅ ∠LBA

m∠LBA = 30°

Now from right triangle ΔLDC,

sin(∠LBA) =

sin(30)° =

LD = 0.6

Therefore, Distance of point L from AB is 0.6 in.

m∠ABC = m∠ABL + m∠LBC

             = 30° + 30°

             = 60°

it should be a and d. lmk if i'm wrong xd

ca = ec

cpctc makes it so that corresponding parts of the triangle you proved to be equal are equal, the other options aren't part of the part of the triangles you proved to be equal.