6. Consider the polynomial p(x) = x^2 + kr^2 +x+6. Find a value of k so that x+1 is a factor of P. Find all the zeros of P.

If x + 1 is a factor of p(x) = x³ + k x² + x + 6, then by the remainder theorem, we have

p (-1) = (-1)³ + k (-1)² + (-1) + 6 = 0   →   k = -4

So we have

p(x) = x³ - 4x² + x + 6

Dividing p(x) by x + 1 (using whatever method you prefer) gives

p(x) / (x + 1) = x² - 5x + 6

Synthetic division, for instance, might go like this:

-1   |   1    -4     1     6

...   |         -1    5    -6

...   |   1    -5    6     0

Next, we have

x² - 5x + 6 = (x - 3) (x - 2)

so that, in addition to x = -1, the other two zeros of p(x) are x = 3 and x = 2

a² + b²= c²

24² + 7² = c²

c= 25

in the math equation 8 x 7 = 56, the 8 and the 7 are both factors of 56, since in this lesson we will use square tiles to figure out the factors of a whole find as many different arrays as you can, but follow one important rule: all the rows must have the i can make two rows of nine, so 2 and 9 are both factors of 18.

step-by-step explanation: