What is the distance between (6, 1) and (1, -9)?

Answer: √15 units

Step-by-step explanation:

Let (6,1) be (x^1,y^1) and (1,-9) be (x^2,y^2) .

As we know ,

Distance(D) = √(x^1-x^2) +(y^1-y^2)

Now,

D= √(x^1-x^2) +(y^1-y^2)

= √(6-1) +(1+9)

= √5+10

= √15 units

: Therefore the distance between (6,1) and (1,-9) is √15 units.