Using the quadratic formula to solve x2 = 5-x, what are the values of x?

its the first choice, negative 1 plus or minus square root of 21 over 2

Step-by-step explanation:

A) (-1 ± √21)/ 2

Step-by-step explanation:

Move all terms onto one side

          = 5-x

+ x - 5 = 0

Insert values into quadratic formula

a = 1      b= 1     c= - 5

[-b ± √( - 4ac)]/2a

[-1 ± √( - 4 (1(-5)]/ 2(1)

(-1 ± √21)/ 2

answer: standard form is ax^2 + bx + c = 0

step-by-step explanation:

standard form is ax^2 + bx + c = 0

(2x + 1)(x - 2) = 0

distribute to get into standard form

2x^2 - 4x + x - 2 = 0

2x^2 - 3x - 2 = 0

a = 2, b= -3, c = -2

a is your answer

its an acute right triangle

step-by-step explanation: