What is the equation of a line, in point-slope form, that passes through (−2, −6)and has a slope of 13? y−6=13(x−2)

y+2=13(x+6)

y+6=13(x+2)

y−2=13(x−6)

The answer is

Step-by-step explanation:

To find an equation of a line in point slope form when given the slope and a point we use the formula

where

m is the slope

( x1 , y1) is the point

From the question we have the final answer as

Hope this helps you

a)(x-2)^2+(y-1)^2=9

step-by-step explanation:

(picture explains)

take the logarithm of both sides (the base of the log doesn't matter):

apply the exponent property - this says that :

distribute the log terms on both sides:

group like terms together:

divide through both sides by the coefficient on :

you can do some additional rewriting here using the properties of the logarithm to simplify things if you like: